225/88ra arrow 0/0 y + blank/88 ra

Question

The number in the box is and this is a form of decay.



Blank 1:
Blank 2:

Answer 1

To analyze the given equation:

You have the notation resembling a radioactive decay equation or a nuclear reaction. Here it seems like \( ^{225}_{88}Ra \) (Radium-225) is decaying.

The general form of a radioactive decay reaction can be expressed as follows:

\[ ^{A}{Z}X \rightarrow ^{A'}{Z'}Y + ^{B'}_{Z''}Z \]

In this case:

• \( ^{225}_{88}Ra \) is the parent nuclide (Radium-225)
• The \( y \) represents the product(s) of the decay.

Currently, the specific details of the decay mode (like alpha, beta, or gamma decay) are not mentioned, but it's common for Radium isotopes to undergo alpha decay due to their heavy nature.

If Radium-225 undergoes alpha decay, we can write:

\[ ^{225}{88}Ra \rightarrow ^{221}{86}Rn + ^{4}_{2}\alpha \]

This means:

• Blank 1: 4 (this represents the mass number of the alpha particle)
• Blank 2: Alpha decay (this describes the type of decay)

So, completing the blanks, we have:

Blank 1: 4
Blank 2: Alpha decay