Question
you push a physics book 1.50m along a horizontal tabletop with a horizontal push of 2.40 N while the opposing force of friction is 0.600 N. How much work does each of the follwing forces do on the book? A) you 2.40N push. B) the friction force. C) the normal force from the table and D) gravity? E) what is the net work done on the book?
Answers
a table exerts a 2.0 -newton force on a book lying on the table. how much force is exerted by the book on the table?
A) 2.40*1.50=3.6J
b) -0.600*1.50=-0.9
c) (1.50)cos90=0
d) same as c
E) 3.6-0.9=2.7
b) -0.600*1.50=-0.9
c) (1.50)cos90=0
d) same as c
E) 3.6-0.9=2.7
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