Asked by Randy
When you push a 1.82-kg book resting on a tabletop, it takes 2.30 N to start the book sliding. Once it is sliding, however, it takes only 1.46 N to keep the book moving with constant speed.
Q1. What is the coefficient of static friction between the book and the tabletop?
Q2. What is the coefficient of kinetic friction between the book and the tabletop?
Q1. What is the coefficient of static friction between the book and the tabletop?
Q2. What is the coefficient of kinetic friction between the book and the tabletop?
Answers
Answered by
drwls
Q1: 2.30 = M*g*mus
mus = 2.30/(M*g) = 0.129
Q2: 1.46 = M*g*muk
muk = 1.46/(M*g) = ___
mus = 2.30/(M*g) = 0.129
Q2: 1.46 = M*g*muk
muk = 1.46/(M*g) = ___
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