Asked by Aparicio
write a net ionic equation for?
2KI + Pb(NO3)2 ==>2KNO3 + PbI2
This is my answer below
2I^- + NO3==>2No3 +I2^-
can anyone tell me if this is the correct answer
2KI + Pb(NO3)2 ==>2KNO3 + PbI2
This is my answer below
2I^- + NO3==>2No3 +I2^-
can anyone tell me if this is the correct answer
Answers
Answered by
GK
The reaction is:
KI(aq) + Pb(NO3)2(aq) --> 2KNO3(aq) + PbI2(s)
The net reaction is the formation of the PbI2(s) as a precipitate. You figure that by applying solubility rules of ionic compounds. The net reaction includes the ions that help form PbI2(s):
Pb^2+(aq) + 2I^-(aq) --> PbI2(s)
KI(aq) + Pb(NO3)2(aq) --> 2KNO3(aq) + PbI2(s)
The net reaction is the formation of the PbI2(s) as a precipitate. You figure that by applying solubility rules of ionic compounds. The net reaction includes the ions that help form PbI2(s):
Pb^2+(aq) + 2I^-(aq) --> PbI2(s)
Answered by
jeniffer
the reaction is a metathesis therefore the ions are completely dissociated.
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