Asked by Sid
write the net ionic equation of the following reaction:
HCl(aq)+NaOH(aq)--> NaCl(aq)+H2O(l)
HCl(aq)+NaOH(aq)--> NaCl(aq)+H2O(l)
Answers
Answered by
DrBob222
It helps us if you don't change screen names. Do you know how to do these? There is a procedure to follow.
1. Convert molecular equation to TOTAL ionic equation following these rules:
a. gases are written as molecules.
b. insoluble materials are written as molecules.
c. weak electrolytes are written as molecules.
d. all others are written as ions.
H^+)aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) ==> Na^+(aq) + Cl^-(aq) + H2O(l)
2. Now cancel substances that appear on both sides of the equation. So I cancel Na^+(aq) and Cl^-(aq)
3. The result is the NET ionic equation
H^+(aq) + OH^-(aq) ==> H2O(l).
1. Convert molecular equation to TOTAL ionic equation following these rules:
a. gases are written as molecules.
b. insoluble materials are written as molecules.
c. weak electrolytes are written as molecules.
d. all others are written as ions.
H^+)aq) + Cl^-(aq) + Na^+(aq) + OH^-(aq) ==> Na^+(aq) + Cl^-(aq) + H2O(l)
2. Now cancel substances that appear on both sides of the equation. So I cancel Na^+(aq) and Cl^-(aq)
3. The result is the NET ionic equation
H^+(aq) + OH^-(aq) ==> H2O(l).
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