F(net) = F-F(res) =(2.06-1.75)•10³=0.31•10³=310 N
a=F(net)/m= 310/1300=0.24 m/s²
s=at²/2=…
v=at = …
A boat moves through the water with two forces acting on it. One is a 2.06 103 N forward push by a motor, and the other is a 1.75 103 N resistive force due to the water.
a)What is the acceleration of the 1300 kg boat?
b)If it starts from rest, how far will it move in 11 s?
c)hat will its speed be at the end of its time interval?
1 answer
1 answer