Asked by ken
A boat moves through the water with two forces acting on it. One is a 2.05 103 N forward push by a motor, and the other is a 1.75 103 N resistive force due to the water.
(a) What is the acceleration of the 1080 kg boat?
(b) If it starts from rest, how far will it move in 9 s?
(c) What will its speed be at the end of its time interval?
(a) What is the acceleration of the 1080 kg boat?
(b) If it starts from rest, how far will it move in 9 s?
(c) What will its speed be at the end of its time interval?
Answers
Answered by
Henry
a. Fn=F1-F2=2050-1750=300 N.,Net force.
Fn = ma.
a = Fn/m = = 300 / 1080 = 0.278 m/s^2.
b. d = Vo*t + 0.5a*t^2.
d = 0 + 0.1388*9^2 = 11.25 m.
c. V = Vo + at = 0 + 0.278*9 = 2.50 m/s.
Fn = ma.
a = Fn/m = = 300 / 1080 = 0.278 m/s^2.
b. d = Vo*t + 0.5a*t^2.
d = 0 + 0.1388*9^2 = 11.25 m.
c. V = Vo + at = 0 + 0.278*9 = 2.50 m/s.
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