a. Fn=F1-F2=2050-1750=300 N.,Net force.
Fn = ma.
a = Fn/m = = 300 / 1080 = 0.278 m/s^2.
b. d = Vo*t + 0.5a*t^2.
d = 0 + 0.1388*9^2 = 11.25 m.
c. V = Vo + at = 0 + 0.278*9 = 2.50 m/s.
A boat moves through the water with two forces acting on it. One is a 2.05 103 N forward push by a motor, and the other is a 1.75 103 N resistive force due to the water.
(a) What is the acceleration of the 1080 kg boat?
(b) If it starts from rest, how far will it move in 9 s?
(c) What will its speed be at the end of its time interval?
1 answer
1 answer