In triangle ABC given, SinA = 1/3, SinB = 3/4, b = 15cm, find a.

1 answer

To find side a, we can use the Law of Sines. This law states that the ratio of the length of a side to the sine of its opposite angle is constant in any triangle. In other words, a/sinA = b/sinB = c/sinC.

From sinA = 1/3, we can rearrange the equation to solve for a:
a = sinA * b
a = (1/3) * 15
a = 5 cm

Therefore, side a is 5 cm.