Asked by Jayd
Calculate the change in heat:
2 Na(s) + 2 H2O(l) > 2 NaOH(aq) + H2(g)
So far this is what I have:
2 H20 --> 2 H2 + O2 2(285.83) kJ
2 Na + O2 + H2 --> 2 NaOH 2(-426.73) kJ
2 Na + 2 H2O --> 2 NaOH + H2 -281.8 kJ
If this correct??
yes, correct, as best as I can tell.
2 Na(s) + 2 H2O(l) > 2 NaOH(aq) + H2(g)
So far this is what I have:
2 H20 --> 2 H2 + O2 2(285.83) kJ
2 Na + O2 + H2 --> 2 NaOH 2(-426.73) kJ
2 Na + 2 H2O --> 2 NaOH + H2 -281.8 kJ
If this correct??
yes, correct, as best as I can tell.