Asked by TaSheanda
What is the heat change in J associated with 44 g of solid methanol at -149 oC changing to liquid at -83 oC?
c(methanol) (liq) = 2.47 J/(g.K)
c(methanol) (s) = 1.85 J/ (g.K)
ÄHfus(methanol) = 3.17 kJ/mol
The freezing point of methanol is -98 oC
c(methanol) (liq) = 2.47 J/(g.K)
c(methanol) (s) = 1.85 J/ (g.K)
ÄHfus(methanol) = 3.17 kJ/mol
The freezing point of methanol is -98 oC
Answers
Answered by
bobpursley
Make a table
heat warming solid=mass*csolid*(-98+149)
heat melting solid to liquid=mass*Hf
heat used heating liquid=mass*cliwuid(-83+98)
add the heats.
heat warming solid=mass*csolid*(-98+149)
heat melting solid to liquid=mass*Hf
heat used heating liquid=mass*cliwuid(-83+98)
add the heats.