Asked by Jess

Calculate the change in heat when 3.05g of water vapor (steam) at 100.0 degrees celsius condenses to liquid water and then cools to 18.50 degrees celsius.
Answered by DrBob222
q1 = heat released by steam at 100 C condensing to water at 100 C..
q1 = mass steam x delta Hvap.

q2 = heat released in cooling from 100 C to 18.5 C.
q2 = mass water x specific heat water x (Tfinal-Tinitial).

Total heat released
qtotal = q1 + q2.
Answered by Anonymous
1040kj
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