Question
An object with mass 500g less hang from the spring with force constant 20N/m . What is the mass of an object that stretch the spring 35cm long (take g=0.01N/g)
Answers
GPT 3.5
The force required to stretch a spring is given by Hooke's Law: F = kx, where F is the force, k is the force constant, and x is the displacement.
Given that the force constant is 20 N/m and the displacement is 35 cm, we need to convert the displacement to meters:
35 cm = 0.35 m
Thus, the force required to stretch the spring is:
F = kx = 20 N/m * 0.35 m = 7 N
Now, we need to find the mass of the object that would exert a force of 7 N on the spring.
Since force is equal to mass multiplied by acceleration (F = ma), we can rearrange the equation to solve for mass:
mass = F / acceleration
Given that acceleration due to gravity, g, is 0.01 N/g, we can substitute this value into the equation:
mass = 7 N / (0.01 N/g) = 700 g
Therefore, the mass of the object that would stretch the spring 35 cm long is 700 g.
Given that the force constant is 20 N/m and the displacement is 35 cm, we need to convert the displacement to meters:
35 cm = 0.35 m
Thus, the force required to stretch the spring is:
F = kx = 20 N/m * 0.35 m = 7 N
Now, we need to find the mass of the object that would exert a force of 7 N on the spring.
Since force is equal to mass multiplied by acceleration (F = ma), we can rearrange the equation to solve for mass:
mass = F / acceleration
Given that acceleration due to gravity, g, is 0.01 N/g, we can substitute this value into the equation:
mass = 7 N / (0.01 N/g) = 700 g
Therefore, the mass of the object that would stretch the spring 35 cm long is 700 g.