Ask a New Question

A 500g mass is placed on a spiral spring and the length of the spring decreases from 13cm to 9cm.calculate the force constant of the spring

3 answers

F = kx
0.5*9.8 = k*4

4 cm = 0.04 meter

oops. way to watch.

Similar Questions

A body of mass 500g suspended from the end of a spiral spring which obeys Hooke's law, produced an extension of 10cm. If the
1. 1 answer
A body of mass 500g suspended from the end of a spiral spring which obeys Hooks law, produced an extension of 10cm. If the mass
1. 1 answer
I NEED HELP ON C THROUGH F. THANK YOUA spring id vertically, as shown below, and a 500g mass is hung from its lower end. The
1. 1 answer
A spring id vertically, as shown below, and a 500g mass is hung from its lower end. The EQUILIBRIUM extension of the spring is
1. 0 answers

more similar questions