Asked by Jackson
A block of mass 500g slides down a ramp that is inclined at 30.0° to the horizontal. The coefficient of kinetic friction is 0.230.
What is the Acceleration?
What is the Acceleration?
Answers
Answered by
Anonymous
normal force of weight = m g cos30
so
Friction force = 0.230 * 0.500 * 9.81 * 0.866 up slope
component of weight down slope = m g sin 30 = 0.500*9.81*0.5
0.500 a = 0.500 * 9.81 *[ 0.5 - 0.230*0.866]
a = 0.3 g = 2.95 m/s^2
so
Friction force = 0.230 * 0.500 * 9.81 * 0.866 up slope
component of weight down slope = m g sin 30 = 0.500*9.81*0.5
0.500 a = 0.500 * 9.81 *[ 0.5 - 0.230*0.866]
a = 0.3 g = 2.95 m/s^2
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