Asked by tina
jerome morgan and bly compete in a 10 kilometer race with 5 other athletes. what are the odds that they finish in the top 3 places? i got 3 to 5 but my teacher marked it wrong and wanted us to find out why it was wrong on our own. help would be nice!
Answers
Answered by
Damon
Make a table
--B1 B2 B3 B4 B5 B6 B7
J1 --y- y- n- n- n- n-
J2 y -- y- n- n- n- n-
J3 y y- -- n- n- n- n-
J4 n n- n- -- n- n- n-
J5 n n- n- n- -- n- n-
J6 n n- n- n- n- -- n-
J7 n n- n- n- n- n- --
The diagonal elemnts are not part of our possibilities because they can no both finish in the same position.
That leaves us with 42 possible outcomes
of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.
6/42 =3/21
--B1 B2 B3 B4 B5 B6 B7
J1 --y- y- n- n- n- n-
J2 y -- y- n- n- n- n-
J3 y y- -- n- n- n- n-
J4 n n- n- -- n- n- n-
J5 n n- n- n- -- n- n-
J6 n n- n- n- n- -- n-
J7 n n- n- n- n- n- --
The diagonal elemnts are not part of our possibilities because they can no both finish in the same position.
That leaves us with 42 possible outcomes
of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.
6/42 =3/21
Answered by
Damon
Make a table
--b1 b2 b3 b4 b5 b6 b7
J1 --y- y- n- n- n- n-
J2 y -- y- n- n- n- n-
J3 y y- -- n- n- n- n-
J4 n n- n- -- n- n- n-
J5 n n- n- n- -- n- n-
J6 n n- n- n- n- -- n-
J7 n n- n- n- n- n- --
The diagonal elements are not part of our possibilities because they can no both finish in the same position.
That leaves us with 42 possible outcomes
of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.
6/42 =3/21
--b1 b2 b3 b4 b5 b6 b7
J1 --y- y- n- n- n- n-
J2 y -- y- n- n- n- n-
J3 y y- -- n- n- n- n-
J4 n n- n- -- n- n- n-
J5 n n- n- n- -- n- n-
J6 n n- n- n- n- -- n-
J7 n n- n- n- n- n- --
The diagonal elements are not part of our possibilities because they can no both finish in the same position.
That leaves us with 42 possible outcomes
of those 42, six are y which means six of the 42 outcomes have both B and J in the first 3 places.
6/42 =3/21
Answered by
Damon
I can not get columns to line up no matter what I do using -- or - for spacers
you have 7 rows and seven columns
the diagonals, marked with -- are out because J and B can not finish in the same place.
The y solutions are the good ones.
The n solutions are no good.
you have 7 rows and seven columns
the diagonals, marked with -- are out because J and B can not finish in the same place.
The y solutions are the good ones.
The n solutions are no good.
Answered by
tina
there are 3 people not only 2
Answered by
tina
you left out morgan
Answered by
Reiny
the number of ways for J, M and B and 5 others can be arranged is
3!5!.
The number of ways all 8 can be arranged is 8!
so the prob that they will be the first 3 finishers
= 3!5!/8! = 1/56
but you asked for the odds
odds of some event = prob the event will happen : prob the event will not happen
= (1/56):(55/56)
= 1 : 55
3!5!.
The number of ways all 8 can be arranged is 8!
so the prob that they will be the first 3 finishers
= 3!5!/8! = 1/56
but you asked for the odds
odds of some event = prob the event will happen : prob the event will not happen
= (1/56):(55/56)
= 1 : 55
Answered by
megan
For Jerome the chances are 3/8 (if all of the runners had equal ability). For Morgan, after Jerome had gotten first (let's say he did) then his chances would be 2/7. And for Bly his chances are 1/6. Now you have got to multiply them all together.
(3/8) (2/6) (1/6) = 1/56
i feel like this is the easy way of doing it...
(3/8) (2/6) (1/6) = 1/56
i feel like this is the easy way of doing it...
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