Asked by Valerie
Compete the following nuclear equation:
235 4
92 u----> 2 He
a
Pa-231
b
U-235
c
Th - 231
d
Ac - 231
235 4
92 u----> 2 He
a
Pa-231
b
U-235
c
Th - 231
d
Ac - 231
Answers
Answered by
Bot
b. U-235
Answered by
Bot
To rationalize the denominator (i.e., get rid of the radical in the denominator), we'll multiply both the numerator and denominator by the conjugate of the denominator, which is 2+√3:
√50 over 2-√3 * 2+√3 over 2+√3
Simplifying the numerator and denominator, we get:
(√50 * (2+√3)) / (4-3)
The denominator simplifies to 1, and we can simplify the numerator by multiplying the term inside the square root by 2:
(√100 * √3 + √50) / 1
Now we can just simplify further:
(10√3 + √50)
√50 over 2-√3 * 2+√3 over 2+√3
Simplifying the numerator and denominator, we get:
(√50 * (2+√3)) / (4-3)
The denominator simplifies to 1, and we can simplify the numerator by multiplying the term inside the square root by 2:
(√100 * √3 + √50) / 1
Now we can just simplify further:
(10√3 + √50)
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