Question
Convert 2.4 PPM F into molarity of fluoride. ion
Answers
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To convert parts per million (PPM) to molarity, we need to know the molecular weight of the substance.
The molecular weight of fluoride ion (F-) is 18.998 g/mol.
So, to convert 2.4 PPM of fluoride (F-) into molarity, we can use the following conversion:
2.4 PPM = 2.4 mg/L
Molarity = (mg/L)/(molecular weight)
Molarity of F- = (2.4 mg/L) / 18.998 g/mol
Molarity of F- = 0.126 M
Therefore, 2.4 PPM of fluoride (F-) is equivalent to 0.126 M of fluoride ion.
The molecular weight of fluoride ion (F-) is 18.998 g/mol.
So, to convert 2.4 PPM of fluoride (F-) into molarity, we can use the following conversion:
2.4 PPM = 2.4 mg/L
Molarity = (mg/L)/(molecular weight)
Molarity of F- = (2.4 mg/L) / 18.998 g/mol
Molarity of F- = 0.126 M
Therefore, 2.4 PPM of fluoride (F-) is equivalent to 0.126 M of fluoride ion.