Convert 2.4 PPM F into molarity of fluoride. ion

Answer 1

To convert parts per million (PPM) to molarity, we need to know the molecular weight of the substance.

The molecular weight of fluoride ion (F-) is 18.998 g/mol.

So, to convert 2.4 PPM of fluoride (F-) into molarity, we can use the following conversion:

2.4 PPM = 2.4 mg/L

Molarity = (mg/L)/(molecular weight)

Molarity of F- = (2.4 mg/L) / 18.998 g/mol

Molarity of F- = 0.126 M

Therefore, 2.4 PPM of fluoride (F-) is equivalent to 0.126 M of fluoride ion.