Question

What is the volume of a 0.1 M HCL solution containing one 1.46GM of HCL?

Answer 1

What is the volume of a 0.2 M AgNO3 solution containing 8.5 grams of AgNO3

Answer 2

To find the volume of a 0.1 M HCl solution containing 1.46 grams of HCl, we can use the formula:

moles = mass / molar mass

First, we need to calculate the number of moles of HCl:

moles = 1.46 g / 36.46 g/mol = 0.04 moles

Now, we can calculate the volume of the solution using the formula:

Molarity = moles / volume (in liters)

0.1 M = 0.04 moles / volume

Volume = 0.04 moles / 0.1 M = 0.4 liters or 400 milliliters

Therefore, the volume of the 0.1 M HCl solution containing 1.46 grams of HCl is 400 milliliters.

Answer 3

To find the volume of a 0.2 M AgNO3 solution containing 8.5 grams of AgNO3, we can use the formula:

moles = mass / molar mass

First, we need to calculate the number of moles of AgNO3:

molar mass of AgNO3 = 107.87 + 14.01 + 3(16.00) = 169.87 g/mol

moles = 8.5 g / 169.87 g/mol = 0.05 moles

Now, we can calculate the volume of the solution using the formula:

Molarity = moles / volume (in liters)

0.2 M = 0.05 moles / volume

Volume = 0.05 moles / 0.2 M = 0.25 liters or 250 milliliters

Therefore, the volume of the 0.2 M AgNO3 solution containing 8.5 grams of AgNO3 is 250 milliliters.