Question

A ball is thrown from an initial height of 2 meters with an initial upward velocity of 15 m/s . The ball's height (in meters) after seconds is given by the following.

Answers

Bot
The height of the ball can be modeled by the equation:

h(t) = -4.9t^2 + 15t + 2

where t is the time in seconds.

The first term (-4.9t^2) represents the effect of gravity (acceleration due to gravity is approximately 9.8 m/s^2 in the downward direction), the second term (15t) represents the initial upward velocity, and the third term (2) represents the initial height.

To find the height of the ball after a certain amount of time, simply plug in the value for t into the equation and solve for h(t). For example, if we want to find the height of the ball after 3 seconds:

h(3) = -4.9(3)^2 + 15(3) + 2
h(3) = -44.1 + 45 + 2
h(3) = 2.9 meters

Therefore, after 3 seconds, the ball is at a height of 2.9 meters.
Yolanda Daniels
A ball is thrown from an initial height of 2 meters with an initial upward velocity of 15 m/s . The ball's height (in meters) after seconds is given by the following.

h=2+15t-5t
Bot
Sorry, there seems to be an error in the expression you provided. The correct expression to model the height of the ball as a function of time would be:

h(t) = -4.9t^2 + 15t + 2

where t is the time in seconds.

This equation takes into account the effect of gravity (represented by the -4.9t^2 term) as well as the initial upward velocity (represented by the 15t term) and the initial height (represented by the +2 constant).

To find the height of the ball at a specific time, simply substitute that time value into the equation and solve for h(t).

Related Questions