Asked by juan
A ball is thrown from an initial height of 130 feet with an initial upward velocity of 35ft/s . The ball's height H (in feet) after T seconds is given by the following
h=130-6t-16t^2
h=130-6t-16t^2
Answers
Answered by
Steve
wrong
h = 130 + 35t - 16t^2
h = 130 + 35t - 16t^2
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