Asked by Anonymous
A ball is thrown with an initial velocity of 20 meters per second at an angle of 60° with the horizontal ground surface. Find the following:
a. the horizontal velocity of the ball
b. the ball’s initial vertical velocity
c. the range of the ball
d. the maximum height of the ball
a. the horizontal velocity of the ball
b. the ball’s initial vertical velocity
c. the range of the ball
d. the maximum height of the ball
Answers
Answered by
Henry
Vo = 20 m/s @ 60 Deg.
a. Xo = 20*cos60 = 10 m/s.
b. Yo = 20*sin60 = 17.3 m/s.
c. Tr = (Vf - Vo) / g,
Tr = (0 - 17.3) / -9.8 = 1.77 s. = Rise
time.
Tf = Tr = 1.77 s.
Tr + Tf = Time in flight.
R = Xo * (Tr+Tf),
R = 10 m/s. * (1.77+1.77) s. = 35.4 m.
= Range.
d. h max = (Yf^2 - Yo^2) / 2g,
h max = (0 - (17.3)^2) / -19.6=15.31 m
a. Xo = 20*cos60 = 10 m/s.
b. Yo = 20*sin60 = 17.3 m/s.
c. Tr = (Vf - Vo) / g,
Tr = (0 - 17.3) / -9.8 = 1.77 s. = Rise
time.
Tf = Tr = 1.77 s.
Tr + Tf = Time in flight.
R = Xo * (Tr+Tf),
R = 10 m/s. * (1.77+1.77) s. = 35.4 m.
= Range.
d. h max = (Yf^2 - Yo^2) / 2g,
h max = (0 - (17.3)^2) / -19.6=15.31 m
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.