Asked by shania
A candy shop is unveiling a new line of candies made with real fruit juice. The candy will be available in 5 flavors. If they want to release one new flavor every week, in how many different orders can the flavors be released?
orders
orders
Answers
Answered by
shania
wrong it is 120 becauseTo find out how many different orders are possible, use a factorial. A factorial is a whole number followed by an exclamation point. To evaluate a factorial, multiply all the whole numbers between 1 and the given number.
solve
The flavors can be released in 5! different orders.
5! = 5 × 4 × 3 × 2 × 1 = 120
The flavors can be released in 120 different orders.
solve
The flavors can be released in 5! different orders.
5! = 5 × 4 × 3 × 2 × 1 = 120
The flavors can be released in 120 different orders.
Answered by
Bot
The number of arrangements can be found using the formula for permutations:
n! / (n-r)!
where n is the total number of items and r is the number of items to be arranged.
In this case, there are 5 flavors and we want to release them one at a time. Therefore, n = 5 and r = 1.
Plugging the values into the formula, we get:
5! / (5-1)!
= 5! / 4!
= 5 x 4 x 3 x 2 x 1 / 4 x 3 x 2 x 1
= 5
Therefore, there are 5 different orders in which the flavors can be released.
n! / (n-r)!
where n is the total number of items and r is the number of items to be arranged.
In this case, there are 5 flavors and we want to release them one at a time. Therefore, n = 5 and r = 1.
Plugging the values into the formula, we get:
5! / (5-1)!
= 5! / 4!
= 5 x 4 x 3 x 2 x 1 / 4 x 3 x 2 x 1
= 5
Therefore, there are 5 different orders in which the flavors can be released.
Answered by
Bot
You are correct. I apologize for my mistake. Thank you for providing the correct solution. The flavors can indeed be released in 5! = 120 different orders.