Asked by bob
1.) The width w of a rectangular swimming pool is x+4. the area a of the pool is x^3-13x+12. What is an expression for the length of the pool?
A.) X^2+4x+3
B.) X^2-4x-3
C.) X^2-4x+3
D.) X^2+4x-3
2.)Katalin drove 180 miles on her vacation. She drove an average of 1.5 times faster on the second 90 miles of her trip than she did on the first 90 miles of her trip. Which expression represents the time she spent driving? Let x = her speed on the first half of the trip.
A.) 150/x
B.) 300/x
C.) 150x
D.) 225/x
3.)Simplify x/6x-x^2
A.) 1/6-x; where x is not equal to 0,6
B.) 1/6-x; where x is not equal to 6
C.) 1/6x; where x is not equal to 0
D.) 1/6
A.) X^2+4x+3
B.) X^2-4x-3
C.) X^2-4x+3
D.) X^2+4x-3
2.)Katalin drove 180 miles on her vacation. She drove an average of 1.5 times faster on the second 90 miles of her trip than she did on the first 90 miles of her trip. Which expression represents the time she spent driving? Let x = her speed on the first half of the trip.
A.) 150/x
B.) 300/x
C.) 150x
D.) 225/x
3.)Simplify x/6x-x^2
A.) 1/6-x; where x is not equal to 0,6
B.) 1/6-x; where x is not equal to 6
C.) 1/6x; where x is not equal to 0
D.) 1/6
Answers
Answered by
Bot
B.) 1/6-x; where x is not equal to 6
Answered by
bob
Bot, what are the answers to ALL of the questions
Answered by
Bot
1.) C) X^2-4x+3
2.) A) 150/x
3.) B) 1/6-x; where x is not equal to 6
2.) A) 150/x
3.) B) 1/6-x; where x is not equal to 6
Answered by
bob
Do the data in the table represent a direct variation or an inverse variation? Write an equation to model the data in the table.
x 1 2 5 10
y 6 12 30 60
x 1 2 5 10
y 6 12 30 60
Answered by
Bot
The data in the table represent a direct variation because as x increases, so does y.
We can write an equation to model the data as:
y = kx
To find k (the constant of variation), we can use any x-y pair from the table. Let's use the first one (1, 6):
6 = k(1)
k = 6
Therefore, the equation to model the data is:
y = 6x
We can write an equation to model the data as:
y = kx
To find k (the constant of variation), we can use any x-y pair from the table. Let's use the first one (1, 6):
6 = k(1)
k = 6
Therefore, the equation to model the data is:
y = 6x
Answered by
bob
simplify. x-2/x^2+4x-12
Answered by
Bot
We can first factor the denominator:
x^2 + 4x - 12 = (x + 6)(x - 2)
Then we can rewrite the expression:
(x - 2)/[(x + 6)(x - 2)]
We can cancel out the common factor of x - 2 in the numerator and denominator:
1/(x + 6)
Therefore, the simplified expression is:
1/(x + 6)
x^2 + 4x - 12 = (x + 6)(x - 2)
Then we can rewrite the expression:
(x - 2)/[(x + 6)(x - 2)]
We can cancel out the common factor of x - 2 in the numerator and denominator:
1/(x + 6)
Therefore, the simplified expression is:
1/(x + 6)
Answered by
bob
simplify. x-2/x^2+4x-12
A.) 1/x+6; where x is not equal to 0,6
B.) 1/x+6; where x is not equal to 6
A.) 1/x+6; where x is not equal to 0,6
B.) 1/x+6; where x is not equal to 6
Answered by
Bot
B.) 1/x+6; where x is not equal to 6
Answered by
bob
simplify. x-2/x^2+4x-12
A.) 1/x+6; where x is not equal to -6
B.) 1/x+6; where x is not equal to 6,2
A.) 1/x+6; where x is not equal to -6
B.) 1/x+6; where x is not equal to 6,2
Answered by
Bot
It should be:
A.) 1/(x+6); where x is not equal to -6.
The simplified expression is 1/(x+6), but we need to exclude the value -6 from the domain, because that would make the denominator 0 and create an undefined expression.
A.) 1/(x+6); where x is not equal to -6.
The simplified expression is 1/(x+6), but we need to exclude the value -6 from the domain, because that would make the denominator 0 and create an undefined expression.
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