Asked by Anonymous
a perimeter of the rectangula land is 500m if the length and the breath of that rectangular land is 2:3 ratio,find the area of rectangel
Answers
Answered by
Bosnian
P = 2 ( L + B ) = 500
2 ( L + B ) = 500
Divide both sides by 2
L + B = 250
L / B = 2 / 3
Cross multiply:
3 L = 2 B
L = ( 2 / 3 ) B = 2 B / 3
L + B = 250
Replace L with 2 B / 3 in this equation
2 B / 3 + B = 250
2 B / 3 + 3 B / 3 = 250
5 B / 3 = 250
Multiply both sides by 3
5 B = 750
Divide both sides by 5
B = 150 m
L = 2 B / 3 = 2 ∙ 150 / 3 = 300 / 3 = 100 m
A = L ∙ B = 100 ∙ 150 = 15 000 m²
2 ( L + B ) = 500
Divide both sides by 2
L + B = 250
L / B = 2 / 3
Cross multiply:
3 L = 2 B
L = ( 2 / 3 ) B = 2 B / 3
L + B = 250
Replace L with 2 B / 3 in this equation
2 B / 3 + B = 250
2 B / 3 + 3 B / 3 = 250
5 B / 3 = 250
Multiply both sides by 3
5 B = 750
Divide both sides by 5
B = 150 m
L = 2 B / 3 = 2 ∙ 150 / 3 = 300 / 3 = 100 m
A = L ∙ B = 100 ∙ 150 = 15 000 m²
Answered by
henry2,
L = 2x, W = 3x, P = 500 m., A = ?.
P = 2*2x+2*3x = 500
4x+6x = 500
X = 50.
L = 2x = 2*50 = 100 m.
W = 3x = 3*50 = 150 m.
A = L*W = 100*150 = 15,000 m^2.
P = 2*2x+2*3x = 500
4x+6x = 500
X = 50.
L = 2x = 2*50 = 100 m.
W = 3x = 3*50 = 150 m.
A = L*W = 100*150 = 15,000 m^2.
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