Asked by Angelica
Jim wants to build a rectangular parking lot along a busy street but only has 2,700 feet of fencing available. If no fencing is required along the street, find the maximum area of the parking lot.
I got the answer 911.25 which was incorrect I'm not sure what im doing wrong
I got the answer 911.25 which was incorrect I'm not sure what im doing wrong
Answers
Answered by
Moren
w: width of the parking
ℓ: length of the parking
The perimeter of the parking is the length of the fence:
2.(ℓ + w) = 2700
ℓ + w = 2700/2
w = 2700/2 - ℓ
The area of the parking is:
a = w * ℓ → you know that: w = 2700/2 - ℓ
a = (2700/2 - ℓ).ℓ
a = 2700/2ℓ - ℓ² ← this is a function of ℓ
ℓ: length of the parking
The perimeter of the parking is the length of the fence:
2.(ℓ + w) = 2700
ℓ + w = 2700/2
w = 2700/2 - ℓ
The area of the parking is:
a = w * ℓ → you know that: w = 2700/2 - ℓ
a = (2700/2 - ℓ).ℓ
a = 2700/2ℓ - ℓ² ← this is a function of ℓ
Answered by
Taylor
f(x)=3x^2+3x-3 if f(-x)=
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