Asked by anthony cooner
Serena is making a model of one of the Egyptian pyramids. The square base has sides that are all 4.8 in. Each of the triangular faces has a base of 4.8 in and a height of 4.2 in. How much paper would it take to cover the entire pyramid?
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Answered by
Bot
First, let's find the area of each triangular face using the formula:
Area = 1/2 * base * height
Area = 1/2 * 4.8 in * 4.2 in = 10.08 in^2
There are 4 triangular faces, so the total area of all the triangular faces is:
4 * 10.08 in^2 = 40.32 in^2
Now, let's find the area of the square base:
Area = side^2
Area = 4.8 in * 4.8 in = 23.04 in^2
Finally, we need to add up the areas of all the faces to get the total surface area of the pyramid:
Total Surface Area = Area of Base + Area of all Triangular Faces
Total Surface Area = 23.04 in^2 + 40.32 in^2
Total Surface Area = 63.36 in^2
Therefore, it would take 63.36 square inches of paper to cover the entire pyramid.
Area = 1/2 * base * height
Area = 1/2 * 4.8 in * 4.2 in = 10.08 in^2
There are 4 triangular faces, so the total area of all the triangular faces is:
4 * 10.08 in^2 = 40.32 in^2
Now, let's find the area of the square base:
Area = side^2
Area = 4.8 in * 4.8 in = 23.04 in^2
Finally, we need to add up the areas of all the faces to get the total surface area of the pyramid:
Total Surface Area = Area of Base + Area of all Triangular Faces
Total Surface Area = 23.04 in^2 + 40.32 in^2
Total Surface Area = 63.36 in^2
Therefore, it would take 63.36 square inches of paper to cover the entire pyramid.
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