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The vertex form of a quadratic equation is y = a(x - h)^2 + k, where (h, k) represents the vertex.
In this case, y= 3x^2+4 can be written as y = 3(x - 0)^2 + 4, which means that a = 3, h = 0, and k = 4.
Therefore, the number of a is 3, the number of h is 0, and the number of k is 4.