Question
What is the vertex form of the graphed equation?
2, -14)
(1 point)
y=
𝑦
=
(x−
𝑥
−
)2+
2
+
2, -14)
(1 point)
y=
𝑦
=
(x−
𝑥
−
)2+
2
+
Answers
GPT-4o mini
To find the vertex form of a quadratic equation, we typically express it in the format:
\[
y = a(x - h)^2 + k
\]
where \((h, k)\) is the vertex of the parabola.
From your message, it seems you provided the point (2, -14) as the vertex of the parabola. This implies that \(h = 2\) and \(k = -14\).
Therefore, the vertex form based on this information would initially look like this:
\[
y = a(x - 2)^2 - 14
\]
Now, we need the value of \(a\) to complete the equation, which generally depends on another point on the parabola or the direction it opens (upward if \(a > 0\) and downward if \(a < 0\)). If you have another point that lies on the curve, please provide it, and I can assist in finding the value of \(a\) and complete the vertex form.
If you do not have another point, then the vertex form of the equation can be simplified to:
\[
y = a(x - 2)^2 - 14
\]
Here, \(a\) can be any non-zero constant, and you would need additional information to specify it.
\[
y = a(x - h)^2 + k
\]
where \((h, k)\) is the vertex of the parabola.
From your message, it seems you provided the point (2, -14) as the vertex of the parabola. This implies that \(h = 2\) and \(k = -14\).
Therefore, the vertex form based on this information would initially look like this:
\[
y = a(x - 2)^2 - 14
\]
Now, we need the value of \(a\) to complete the equation, which generally depends on another point on the parabola or the direction it opens (upward if \(a > 0\) and downward if \(a < 0\)). If you have another point that lies on the curve, please provide it, and I can assist in finding the value of \(a\) and complete the vertex form.
If you do not have another point, then the vertex form of the equation can be simplified to:
\[
y = a(x - 2)^2 - 14
\]
Here, \(a\) can be any non-zero constant, and you would need additional information to specify it.