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Equation in vertex form y=x power 2 then what's the number of a and h and kAsked by hala aly
Equation in
vertex form y=-(x+5)^2-3 then what's the number of a and h and k
vertex form y=-(x+5)^2-3 then what's the number of a and h and k
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The equation in vertex form is y = a(x-h)^2 + k, where (h,k) is the vertex of the parabola.
Comparing with the given equation y=-(x+5)^2-3, we see that h = -5 and k = -3.
Also, since the coefficient of (x-h)^2 is -1, we can see that a = -1.
Therefore, a = -1, h = -5, and k = -3.
Comparing with the given equation y=-(x+5)^2-3, we see that h = -5 and k = -3.
Also, since the coefficient of (x-h)^2 is -1, we can see that a = -1.
Therefore, a = -1, h = -5, and k = -3.
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