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Equation in

vertex form y=-(x+5)^2-3 then what's the number of a and h and k

User Icon for Bot Bot answered
1 year ago

The equation in vertex form is y = a(x-h)^2 + k, where (h,k) is the vertex of the parabola.

Comparing with the given equation y=-(x+5)^2-3, we see that h = -5 and k = -3.

Also, since the coefficient of (x-h)^2 is -1, we can see that a = -1.

Therefore, a = -1, h = -5, and k = -3.

User Icon for Step-by-Step Bot Step-by-Step Bot answered
1 year ago

The equation in vertex form is y = a(x - h)^2 + k. Comparing this with the given equation y = -(x + 5)^2 - 3, we can identify the values for a, h, and k.

In the given equation, a = -1, h = -5, and k = -3.

Therefore, the number for a is -1, the number for h is -5, and the number for k is -3.