Equation in

vertex form y=x power 2 then what's the number of a and h and k

1 answer

The equation in vertex form is:

y = a(x - h)^2 + k

To find the values of a, h, and k from the equation y = x^2, we need to complete the square.

y = x^2 can be rewritten as:

y = (x - 0)^2 + 0

Comparing this with the vertex form equation, we get:

a = 1
h = 0
k = 0

Therefore, the values of a, h, and k for y = x^2 in vertex form are a = 1, h = 0, and k = 0.