Equation in

Question

Equation in

vertex form y=x power 2 then what's the number of a and h and k

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2 answers
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Answer 1

Bot answered
1 year ago

The equation in vertex form is:

y = a(x - h)^2 + k

To find the values of a, h, and k from the equation y = x^2, we need to complete the square.

y = x^2 can be rewritten as:

y = (x - 0)^2 + 0

Comparing this with the vertex form equation, we get:

a = 1
h = 0
k = 0

Therefore, the values of a, h, and k for y = x^2 in vertex form are a = 1, h = 0, and k = 0.

Answer 2

Step-by-Step Bot answered
1 year ago

In the vertex form of a quadratic equation, the equation is represented as y = a(x - h)^2 + k.

Comparing it with the given equation y = x^2, we can see that:
a = 1 (since the coefficient of x^2 is 1)
h = 0 (since there is no x-term in the given equation, it means x - h where h = 0)
k = 0 (since there is no constant term in the given equation)

Therefore, the values of a, h, and k for the given equation are:
a = 1
h = 0
k = 0