Asked by Mitch n' Joey
What is the vertex form of the equation?
y = -x^2+12x-4
My work:
-(x^2 + 12x)-4
-(x^2 + 12x + 36)-4 + 36
Y= -(x+36)^2 + 32
Is this correct? I am not sure if I did this right or not? Thank you!
y = -x^2+12x-4
My work:
-(x^2 + 12x)-4
-(x^2 + 12x + 36)-4 + 36
Y= -(x+36)^2 + 32
Is this correct? I am not sure if I did this right or not? Thank you!
Answers
Answered by
Damon
my try:
x^2 -12 x = -y - 4
x^2 - 12 x + 6^2 = -y -4 + 36
(x-6)^2 = -y + 32
so
(y-32) = -(x-6)^2
vertex at (6 , 32)
x^2 -12 x = -y - 4
x^2 - 12 x + 6^2 = -y -4 + 36
(x-6)^2 = -y + 32
so
(y-32) = -(x-6)^2
vertex at (6 , 32)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.