Asked by Jenny
A 3.48 gram sample of sodium sulfate hydrate lost 1.35 gram of water when heated to constant weight. What is the formula of the hydrate?
this is what I did, but I am stuck.
Na2SO4 . H2O------> NA2SO4+H20
this is what I did, but I am stuck.
Na2SO4 . H2O------> NA2SO4+H20
Answers
Answered by
DrBob222
So the mass of water is what? The loss due to water is the 1.35. How much is left?
3.48 - 1.35 = ?? must be the mass of the anhydrous Na2SO4.
So determine moles Na2SO4 and moles H2O. Convert those moles to small whole numbers just as if you had a percentage problem and want to know the empirical formula.
3.48 - 1.35 = ?? must be the mass of the anhydrous Na2SO4.
So determine moles Na2SO4 and moles H2O. Convert those moles to small whole numbers just as if you had a percentage problem and want to know the empirical formula.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.