Asked by Jessica
How many gram of sodium fluoride should be added to 100000 liter of drinking water containing 0.6 ppm of sodium fluoride to provide a recommended concentration of 1.75 ppm?
Answer is 115 grams. I keep getting .115 g What am I doing wrong? Please help.
Answer is 115 grams. I keep getting .115 g What am I doing wrong? Please help.
Answers
Answered by
Jessica
Nevermind. I figured it out.
Key was 1 ppm is 1mg/L.
1.15 mg/L * 100,000 L = 115,000 mg (115g)
Key was 1 ppm is 1mg/L.
1.15 mg/L * 100,000 L = 115,000 mg (115g)
Answered by
nairem
If a topical cream contains 1.8% (w/w) of hydrocortisone, which of the following strengths is equivalent?
Answered by
Mel
1.75 ppm-0.6 ppm= 1.15 ppm
Since 1 ppm is equivalent to 1 mg/L, 1.15 ppm is equal to 1.15 mg/L.
Therefore,
1.15 mg/L x 100,000L = 115, 000 mg
Since grams are needed, 115, 000 mg x 1g/ 1000 mg = 115 g.
Hope this helps.
Since 1 ppm is equivalent to 1 mg/L, 1.15 ppm is equal to 1.15 mg/L.
Therefore,
1.15 mg/L x 100,000L = 115, 000 mg
Since grams are needed, 115, 000 mg x 1g/ 1000 mg = 115 g.
Hope this helps.
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