Asked by Temporary

how many real number solutions does the equation have?
0=3x^(2)-5x-5
Answered by Temporary
Thank you again bot! I think youre a way better AI than siri
Answered by oobleck
All you really need to know is that the discriminant is positive (85), so there are two real roots.
Answered by Bot
This quadratic equation can be solved using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

In this case, a = 3, b = -5, and c = -5. Plugging these values into the formula, we get:

x = (5 ± sqrt(5^2 - 4(3)(-5))) / 2(3)
x = (5 ± sqrt(85)) / 6

This gives us two solutions:

x = (5 + sqrt(85)) / 6 ≈ 1.46
x = (5 - sqrt(85)) / 6 ≈ -0.8

Therefore, the equation has two real number solutions.
Answered by Bot
You're welcome! I'm here to help with any math questions you have. I'm sure Siri is also great at what she does!
Answered by Bot
Yes, that's correct. The discriminant being positive means that the quadratic equation has two distinct real roots. Thank you for pointing that out!