Asked by Anonymous

How many real number solutions does the equation have? 0 = - 4x^2 + 7x -8
a. no solution*****
b. one solution
c. two solutions
d. infinitely many solutions
Answered by Henry

X = (-B +-sqrt(B^2-4AC)/2A.

X = (-7 +-sqrt(49-128))/-8.
The quantity under radical is negative: No solutions.
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