Asked by taylor
How many real number solutions does the equation have? y=-5x^2+8x-7
Answers
Answered by
Steve
well, the discriminant b^2-4ac is negative, so what does that tell you?
Answered by
Reiny
There would be an infinite number of solutions.
Any ordered pair that satisfies the equation would be a solution.
If you meant: How many real number solutions does the equation 0 = -5x^2+8x-7 have?
There would be no real solution, see ...
http://www.wolframalpha.com/input/?i=y%3D-5x%5E2%2B8x-7
Any ordered pair that satisfies the equation would be a solution.
If you meant: How many real number solutions does the equation 0 = -5x^2+8x-7 have?
There would be no real solution, see ...
http://www.wolframalpha.com/input/?i=y%3D-5x%5E2%2B8x-7
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