Asked by Mehliya (Meh-La)
How many real number solutions are there to the equation 0=-3x^2+x-4
A) 0*****
B) 1
C) 2
D) 3
Help on how to solve this.
A) 0*****
B) 1
C) 2
D) 3
Help on how to solve this.
Answers
Answered by
Steve
recall the discriminant of a quadratic: b^2-4ac
Here, that is 1^2-4(-3)(-4) = 1+48 = 49
since it is positive, there are 2 real roots.
Here, that is 1^2-4(-3)(-4) = 1+48 = 49
since it is positive, there are 2 real roots.
Answered by
Mehliya (Meh-La)
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