Hmm, well try to write a balanced equation
C2 H4 + 3O2 ---> 2CO2 + 2H2O
seems ok
so for every mol of C2H4 I get 2 mol water
C2H4 = 2*12 + 4*1 = 28 grams/mol
so
2 grams is 2/28 = 1/14 of a mol
so
I get 1/7 mol of water
water is 16+2 = 18 grams/mol
18/7 = 2.57 grams of water
2.0 gram of C2H4 is reacted withO2. What mass of water is produced?
3 answers
2.57 grams of water
Hmm, well try to write a balanced equation
C2 H4 + 3O2 ---> 2CO2 + 2H2O
seems ok
so for every mol of C2H4 I get 2 mol water
C2H4 = 2*12 + 4*1 = 28 grams/mol
so
2 grams is 2/28 = 1/14 of a mol
so
I get 1/7 mol of water
water is 16+2 = 18 grams/mol
18/7 = 2.57 grams of water
C2 H4 + 3O2 ---> 2CO2 + 2H2O
seems ok
so for every mol of C2H4 I get 2 mol water
C2H4 = 2*12 + 4*1 = 28 grams/mol
so
2 grams is 2/28 = 1/14 of a mol
so
I get 1/7 mol of water
water is 16+2 = 18 grams/mol
18/7 = 2.57 grams of water