72.1 g of steam is reacted with excess ethene (C2H4) according to the following reaction. Determine the maximum mass (in grams) of ethanol that could be produced.

Question

C2H4 (g) + H2O (g) → C2H5OH (l)

Answer 1

mols H2O = g/molar mass = 72.1/18.01 = 4.0
Convert mols H2O to mols ethanol this way.
4.0 mols H2O x (1 mol ethanol/1 mol H2O) = 4 x /1/1 = 4.0 mols ethanol produced.
Then g ethanol = mols ethanol x molar mass ethanol.
Post your work if you get stuck.

Answer 2

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Answer 3

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Answer 4

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