Find the surface area of a regular pyramid shown to the nearest whole number not drawn to scale

17m
8.5√3m right angle
9m. Slant

A 1209m2
B 790 m2
C 1125 m2
D 898 m2

3 answers

The surface area of a regular pyramid is given by the formula:

SA = (1/2)Pl + B

where P is the perimeter of the base, l is the slant height, and B is the area of the base.

First, let's find the perimeter of the base. Since it is a regular pyramid, the base is a regular hexagon with six equal sides. Each side has length 17m, so the perimeter is:

P = 6(17m) = 102m

Next, let's find the area of the base. Since it is a regular hexagon, we can divide it into six equilateral triangles. Each triangle has base 17m and height (1/2)(8.5√3)m = 4.25√3m. The area of one of these triangles is:

(1/2)(17m)(4.25√3m) = 36.125m^2

So the area of the whole hexagon is:

B = 6(36.125m^2) = 216.75m^2

Finally, let's find the slant height l. We can use the Pythagorean theorem to find the height h of one of the triangles:

h^2 = (8.5√3m)^2 - (4.25m)^2
h^2 = 57.75m^2
h = √57.75m

Then the slant height is:

l^2 = h^2 + (17/2)^2
l^2 = 57.75m + 144.5m
l^2 = 202.25m
l = √202.25m = 14.21m

Now we can plug in these values to the formula for the surface area:

SA = (1/2)(102m)(14.21m) + 216.75m^2
SA = 727.44m^2 + 216.75m^2
SA = 944.19m^2

Rounding to the nearest whole number, the surface area is D) 898m^2.
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