Asked by Piggy
Find the lateral area of a regular hexagonal pyramid with base edge of 10 in and lateral edge of 13 in.
Answers
Answered by
Reiny
you can find the height of each triangle ...
h^2 + 5^2 = 13^2
h = 12
Area of one such triangle = (1/2)base x heigh = (1/2)(10)(12) = 60
there will be 6 such triangles
You don't say if you include the base in the surface area, if so ...
then you can find the area of one of the six equilateral triangles that form the base.
h^2 + 5^2 = 13^2
h = 12
Area of one such triangle = (1/2)base x heigh = (1/2)(10)(12) = 60
there will be 6 such triangles
You don't say if you include the base in the surface area, if so ...
then you can find the area of one of the six equilateral triangles that form the base.
Answered by
Omnom
1/2 PL
P=10*6 because all sides of the hexagon r 10
L=9
60*9/2
270
P=10*6 because all sides of the hexagon r 10
L=9
60*9/2
270
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