Question

Find three consecutive integers whose sum is 132 and show work

Answer 1

Let's call the first of these consecutive integers "x."

Then we know that the second consecutive integer is "x+1" and the third consecutive integer is "x+2."

We also know that the sum of these three integers is 132:

x + (x+1) + (x+2) = 132

Now we can simplify and solve for x:

3x + 3 = 132

3x = 129

x = 43

So the first of the three consecutive integers is 43, and the next two are:

43+1 = 44

43+2 = 45

Therefore, the three consecutive integers whose sum is 132 are 43, 44, and 45.