Asked by Kourtney
Find three consecutive integers odd integers such that the square of the first increased by twice the second is equal to two less than three times the third
Answers
Answered by
oobleck
If the smallest is x, then
x^2 + 2(x+2) = 3(x+4)-2
Unfortunately, this will not work (why?)
To make sure x is odd, we need x = 2k+1
Then we solve
(2k+1)^2 + 2(2k+3) = 3(2k+5)-2
x^2 + 2(x+2) = 3(x+4)-2
Unfortunately, this will not work (why?)
To make sure x is odd, we need x = 2k+1
Then we solve
(2k+1)^2 + 2(2k+3) = 3(2k+5)-2
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