Asked by Kyle
Find three consecutive integers such that, the sum of the first and four times the third is 98.
Thank you!
Thank you!
Answers
Answered by
Bosnian
Numbers are:
A
B = A + 1
C = B + 1 = A + 1 + 1 = A + 2
The sum of the first and four times the third is 98 means;
A + 4 C = 98
A + 4 ∙ ( A + 2 ) = 98
A + 4 A + 8 = 98
5 A + 8 = 98
Subtract 8 to both sides
5 A = 90
A = 90 / 5 = 18
So numbers are:
A = 18
B = A + 1 = 18 + 1 = 19
C = A + 2 = 18 + 2 = 20
18 , 19 , 20
A
B = A + 1
C = B + 1 = A + 1 + 1 = A + 2
The sum of the first and four times the third is 98 means;
A + 4 C = 98
A + 4 ∙ ( A + 2 ) = 98
A + 4 A + 8 = 98
5 A + 8 = 98
Subtract 8 to both sides
5 A = 90
A = 90 / 5 = 18
So numbers are:
A = 18
B = A + 1 = 18 + 1 = 19
C = A + 2 = 18 + 2 = 20
18 , 19 , 20
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