Asked by abraham
Find three consecutive integers such that the square of the third minus the first is equal to 2 more than 5 times the second.
Answers
Answered by
PsyDAG
If they are consecutive, then one = x, the second = x+1 and the third = x+2.
(x-2)^2 - x = 5(x+1) + 2
I'll let you do the calculations.
(x-2)^2 - x = 5(x+1) + 2
I'll let you do the calculations.
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