Asked by purpletree
                Find two consecutive integers, the sum of whose squares is 1 more than twelve times the larger.
(Please provide the steps/explanation for solving this problem)
            
        (Please provide the steps/explanation for solving this problem)
Answers
                    Answered by
            Reiny
            
    two consecutive integers: x and x+1
<the sum of whose squares is 1 more than twelve times the larger..>
x^2 + (x+1)^2 = 12(x+1) + 1
expand and solve as a quadratic equation.
(see if you can come up with 6,7 or -1,0 )
    
<the sum of whose squares is 1 more than twelve times the larger..>
x^2 + (x+1)^2 = 12(x+1) + 1
expand and solve as a quadratic equation.
(see if you can come up with 6,7 or -1,0 )
                    Answered by
            purpletree
            
    Thanks for the help. :)
    
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.