Ask a New Question

Asked by purpletree

Find two consecutive integers, the sum of whose squares is 1 more than twelve times the larger.
(Please provide the steps/explanation for solving this problem)
16 years ago

Answers

Answered by Reiny
two consecutive integers: x and x+1

<the sum of whose squares is 1 more than twelve times the larger..>
x^2 + (x+1)^2 = 12(x+1) + 1

expand and solve as a quadratic equation.
(see if you can come up with 6,7 or -1,0 )
16 years ago
Answered by purpletree
Thanks for the help. :)
16 years ago

Related Questions

find 3 consecutive odd integers such that the product of the first and the second exceeds the third... Find three consecutive integers such that 5 times the first and third is 14 greater than 8 times the... Find three consecutive integers such that the sum of the first and second is three mose than three t... Find three consecutive integers such that, the sum of the first and four times the third is 98. Tha... find 2 consecutive odd integers such that he sum of the smaller and 3 times the larger is 330 Find three consecutive integers whose sum is -78. Find three consecutive integers odd integers such that the square of the first increased by twice th... Find three consecutive integers whose sum is 132 and show work Find three consecutive integers whose sum is 234 Write an equation and solve Find 5 consecutive odd integers if the sum of the first three integers is 3 more than the sum of the...
Ask a New Question
Archives Contact Us Privacy Policy Terms of Use