Asked by mikey
                please help!!!! how do I find three times the first of two consecutive integers is at least twelve more than four times the second. And to find the greatest possible integers.
            
            
        Answers
                    Answered by
            Reiny
            
    Two consecutive integers: x, and x+1
3x > 4(x+1) + 12
3x > 4x + 16
-x > 16
x < -16
So choices would be -16, -15 ... -17, -16 .... -18, -17 ... etc
there are no positive integers that work.
    
3x > 4(x+1) + 12
3x > 4x + 16
-x > 16
x < -16
So choices would be -16, -15 ... -17, -16 .... -18, -17 ... etc
there are no positive integers that work.
                                                    There are no AI answers yet. The ability to request AI answers is coming soon!
                                            
                Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.