Question
One side of a rectangle equals x + 10, and the other is 2x + 3. What is the value of x if the perimeter equals 50?
Answers
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To find the perimeter of a rectangle, you add up the lengths of all four sides. So if one side is x + 10 and the other is 2x + 3, then the perimeter would be:
P = 2(x + 10) + 2(2x + 3)
P = 2x + 20 + 4x + 6
P = 6x + 26
Now we can set this equal to 50 (as the problem states) and solve for x:
6x + 26 = 50
6x = 24
x = 4
Therefore, the value of x is 4.
P = 2(x + 10) + 2(2x + 3)
P = 2x + 20 + 4x + 6
P = 6x + 26
Now we can set this equal to 50 (as the problem states) and solve for x:
6x + 26 = 50
6x = 24
x = 4
Therefore, the value of x is 4.