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How do i get left side to equal right side?
(1-tanx)/(1-cotx) = -tanx
1 answer
(1-tanx)/(1-cotx)
(1-tanx)/(1 - 1/tanx)
(1-tanx)/((tanx-1)/tanx)
(1-tanx)(tanx) / (tanx-1)
-tanx
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For this question, they want me to use fundamental trig identities to simplify the expression. The problem is as follows;
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((cotx+cscx)/(sinx+tanx))=cotxcscx
Please prove left side equal to right side, only doing doing work on the left.
1 answer
((cotx+cscx)/(sinx+tanx))=cotxcscx
Please prove left side equal to right side, only doing doing work on the left.
1 answer
( tanx/1-cotx )+ (cotx/1-tanx)= (1+secxcscx)
Good one! Generally these are done by changing everything to sines and cosines,
0 answers
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