How does hydrochloric acid reacts with the solution of potassium tetraoxomanganate (vii) and give equation

Answer 1

When hydrochloric acid (HCl) reacts with the solution of potassium tetraoxomanganate (VII) (KMnO4), the following redox reaction occurs:

2 KMnO4 + 16 HCl -> 2 KCl + 2 MnCl2 + 5 Cl2 + 8 H2O

In this reaction, permanganate ions (MnO4-) from potassium tetraoxomanganate (VII) are reduced to Mn2+ ions, while chloride ions (Cl-) from hydrochloric acid are oxidized to chlorine gas (Cl2). Potassium ions (K+) and water (H2O) are also produced during the reaction.